The manager of a computer retails store is concerned that his
suppliers have been giving him laptop computers with lower than
average quality. His research shows that replacement times for the
model laptop of concern are normally distributed with a mean of 3.9
years and a standard deviation of 0.4 years. He then randomly
selects records on 53 laptops sold in the past and finds that the
mean replacement time is 3.7 years.
Assuming that the laptop replacement times have a mean of 3.9 years
and a standard deviation of 0.4 years, find the probability that 53
randomly selected laptops will have a mean replacement time of 3.7
years or less.
P(M < 3.7 years) = _______________
Enter your answer as a number accurate to 4 decimal places.
Based on the result above, does it appear that the computer store
has been given laptops of lower than average quality?
Solution :
Given that,
mean = =3.9
standard deviation = = 0.4
n = 53
M = 3.9
M = / n = 0.4 /53 = 0.0549
P(M < 3.7 )
P (M - M) / M < (3.7 - 3.9) / 0.0549))
= P( Z < -0.2 /0.0549)
= P(Z < -3.64)
=0.0001
Probability =0.0001
Yes. The probability of this data is unlikely to have occurred by chance alone.
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