A particular brand of dishwasher soap is sold in three sizes: 30 oz, 35 oz, and 65 oz. Twenty percent of all purchasers select a 30-oz box, 50% select a 35-oz box, and the remaining 30% choose a 65-oz box. Let X1 and X2 denote the package sizes selected by two independently selected purchasers.
a) Determine the sampling distribution of X.
x(bar) | 30 | 32.5 | 35 | 47.5 | 50 | 65 |
P(x) |
B) Calculate E(X). / Compare E(X) to μ.
C) Determine the sampling distribution of the sample variance S2.
s^2 | 0 | 12.5 | 450 | 612.5 |
p(s^2) |
D) Calculate E(S2). / Compare E(S2) to σ2.
(a)
X bar | 30 | 32.5 | 47.5 | 35 | 50 | 65 |
P(X bar) | 0.04 | 0.20 | 0.12 | 0.25 | 0.30 |
0.09 |
(b) Calculate E(X). / Compare E(X) to μ.
sum of all {x bar * p( x bar)} =( 30*0.04)+(32.5*0.20)+(47.5*0.12)+(35*0.25)+(50*0.30)+(65*0.09)
=1.2+6.5+5.7+8.75+15+5.83 = 43
(c) the sampling distribution of the sample variance S2
= Sum of all [ { (X bar - Mean(X bar))^2 } * P (X = X bar) }] ..... for each X bar
= [(30-43)^2]*(0.04) + ... + [(65-43)^2]*(0.09) = 105.5
(d) Calculate E(S2). / Compare E(S2) to σ2.
variance (s^2) = [ (X1-X2)^2 ] / 2
s^2 | 0 | 12.5 | 450 | 612.5 |
P(s^2) | 0.38 | 0.20 | 0.30 | 0.12 |
E(s^2) = (0*0.38) +(12.5*0.20)+(450*0.30)+(612.5*0.12)
= 0+2.5+135+73.5
=211
they are not equal ,E(s^2) = 2 times the variance
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