Question

# In a survey of consumers aged 12 and​ older, respondents were asked how many cell phones...

In a survey of consumers aged 12 and​ older, respondents were asked how many cell phones were in use by the household.​ (No two respondents were from the same​ household.) Among the​ respondents, 217 answered​ "none," 282 said​ "one," 370 said​ "two," 138 said​ "three," and 134 responded with four or more. A survey respondent is selected at random. Find the probability that​ his/her household has four or more cell phones in use. Is it unlikely for a household to have four or more cell phones in​ use? Consider an event to be unlikely if its probability is less than or equal to 0.05.

Given that

Number of households with four or more cellphones = 134

Total households = 217+282+370+138+134

Total households = 1141

We have to find the probability of a randomly selected survey respondent's household having four or more cellphones in use :

P(four or more cell phones) = (Number of households with four or more cellphones)/(Total households)

P(four or more cell phones) = (134)/(217+282+370+138+134)

P(four or more cell phones) = 134/1141

= 0.11744

Therefore the probability of a randomly selected survey respondent's household having four or more cellphones in use is 0.11744

Since, the P(four or more cellphones) = 0.11744 > 0.05, it is NOT unlikely for a household to have four or more cell phones in use.

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