Question

In a random sample of males, it was found that 17 write with their left hands and 221 do not. In a random sample of females, it was found that 64 write with their left hands and 444 do not. Use a 0.05 significance level to test the claim that the rate of left-handedness among males is less than that among females

H0:p1 = p2

H1:P1<P2

and the Z was - 2.23 and P value was 0.013 and the hypothesis conclusion was

P value is Less than the significant level of a =0.05, so reject the null hypothesis. there is significant evidence to support the claim that the rate of left-handedness among males is less than that among females.

and..

the question is i need to find the "Claim by constructing and appropriate confidence interval."

The 90% confidence interval is?? i thought it was - 0.095 <(P1-P2)<-0.014

but the -0.095/-0.014 was not the answer? can you help me to find the confidence interval please?

Answer #1

In a random sample of males, it was found that 21 write with
their left hands and 217 do not.
In a random sample of females, it was found that 63 write with
their left hands and 436 do not.
Use a 0.01 significance level to test the claim that the rate of
left-handedness among males is less than that among females.
Complete parts (a) through (c) below.
a.?Test the claim using a hypothesis test.
Consider the first sample to...

In a random sample of males, it was found that 17 write with
their left hands and 208 do not. In a random sample of females, it
was found that 57 write with their left hands and 445 do not. Use a
0.01 significance level to test the claim that the rate of
left-handedness among males is less than that among females.
Complete parts (a) through (c) below. a. Test the claim using a
hypothesis test. Consider the first sample...

In a random sample of males, it was found that
1818
write with their left hands and
212212
do not. In a random sample of females, it was found that
7070
write with their left hands and
430430
do not. Use a
0.050.05
significance level to test the claim that the rate of
left-handedness among males is less than that among females.
Complete parts (a) through (c) below.
a. Test the claim using a hypothesis test.
Consider the first sample...

In a random sample of males, it was found that 28 write with
their left hands and 210 do not. In a random sample of females, it
was found that 71 write with their left hands and 446 do not. Use a
0.01 significance level to test the claim that the rate of
left-handedness among males is less than that among females.
Identify the test statistic.

a random sample of males, it was found that 25 write with their
left hands and 207 do not. In a random sample of females, it was
found that 70 write with their left hands and 451 do not. Use a
0.01 significance level to test the claim that the rate of
left-handedness among males is less than that among females.
Identify the test statistic and the P-value

Test whether males are less likely than females to support a
ballot initiative, if 24% of a random sample of 50 males plan to
vote yes on the initiative and 32% of a random sample of 50 females
plan to vote yes. Does this scenario represent a confidence
interval or a hypothesis test?

A simple random sample of 100 flights of a large airline (call
this airline 1) showed that 64 were on time. A simple random sample
of 100 flights of another large airline (call this airline 2)
showed that 80 were on time. Let p1 and p2 be the proportion of all
flights that are on time for these two airlines.
If the 90% confidence interval for the difference p1 – p2 is
–0.157 ± 0.102. Is there evidence of a...

Obesity is a topic of ongoing health
concern. A random sample of 25 adult males were examined and found
to be an average of 18 pounds overweight, with a standard deviation
of 10 pounds. These results will be used to address the following
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average, adult males are overweight more than the 15 pounds
reported by a television documentary?
1. Using appropriate notation, state
the null hypothesis and the alternative hypothesis.
2....

The author randomly selected 150 females and 150 males
from the California Health Survey and obtained these results: Among
the 150 females, the mean age is 59.6 years and the standard
deviation is 17.7 years: among the 150 males, the mean age is 59.1
years and the standard deviation is 16.9 years. Using a 0.05
significance level, is there sufficient evidence to support the
claim that the mean age of an adult California female is the same
as the mean...

Suppose it is desired to compare the proportion of male and
female students who voted in the last presidential election. We
decide to randomly and independently sample 1000 male and 1000
female students and ask if they voted or not. A printout of the
results is shown below. Hypothesis Test - Two Proportions Sample
Size Successes Proportion Males 1000 475 0.47500 Females 1000 525
0.52500 Difference -0.05000 Null Hypothesis: p1 = p2 Alternative
Hyp: p1 ≠ p2 SE (difference) 0.02236...

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