Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution. Thirty randomly selected students took the calculus final. If the sample mean was 95 and the standard deviation was 6.6, construct a 99% confidence interval for the mean score of all students.
A.92.95 <μ <97.05
B.92.03 <μ <97.97
C.91.69 <μ <98.31
D.91.68 <μ <98.32
Solution :
Given that,
t /2,df = 2.756
Margin of error = E = t/2,df * (s /n)
= 2.756 * (6.6 / 30)
Margin of error = E = 3.32
The 99% confidence interval estimate of the population mean is,
- E < < + E
95 - 3.32 < < 95 + 3.32
91.68 < < 98.32
option D. is correct
Get Answers For Free
Most questions answered within 1 hours.