The proportion of eligible voters in the State election who will vote for the Premier is assumed to be 53%. What is the probability that in a random sample of 500 voters more than 53% say they will vote for the Premier?
a. 
0.7765 

b. 
0.0734 

c. 
0.2341 

d. 
0.9336 

e. 
0.5000 
probability=
Solution
Given that,
p = 0.53
1  p = 0.47
n = 500
= p =0.53
= [p( 1  p ) / n] = [(0.53*0.47) /500 ] = 0.022
P( >0.53 ) = 1  P( <0.53 )
= 1  P((  ) / < (0.530.53) /0.022 )
= 1  P(z <0 )
Using z table
= 1 0.5000
=0.5000
probability=0.5000
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