The proportion of eligible voters in the next election who will vote for the incumbent is assumed to be 52.8%. What is the probability that in a random sample of 490 voters, less than 49.2% say they will vote for the incumbent?
Solution
Given that,
p = 0.528
1 - p = 1 - 0.528 = 0.472
n = 490
= p = 0.528
= [p ( 1 - p ) / n] = [(0.528 * 0.472) / 490 ] = 0.0226
P( < 0.492)
= P[( - ) / < (0.492 - 0.528) / 0.0226]
= P(z < -1.59)
Using z table,
= 0.0559
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