Question

15. A local newspaper polls 400 voters in an attempt to predict whether the budget will pass. Suppose that the budget actually has the support of 52% of the voters. What is the probability that the newspaper’s sample will lead them to predict defeat (less than 50% support the budget)?

a. 0.212 b. 0.52 c. -0.801 d. 0.025

Answer #1

Solution

_{} = [p ( 1 - p ) / n]
= [(0.52 * 0.48) / 400 ] =
0.025

P( < 0.50) =

= P[( - _{} ) / _{} < (0.50 - 0.52) /
0.025]

= P(z < -0.8)

**= 0.212**

**a)**

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