just before a referendum on a school budget, a local newspaper polls 397 voters to predict whether the budget will pass. Suppose the budget has the support of 55% of the voters. What is the probability that the newspaper's sample will lead it to predict defeat?
Solution
Given that,
p = 0.55
1 - p = 1 - 0.55
n = 397
= p = 0.55
= p ( 1 - p ) / n
= (0.55 * 0.45) / 397 = 0.025
P( < 0.5) =
= P(( - ) / < (0.5 - 0.55) / 0.025)
= P(z < -1)
= 0.1587
Probability = 0.1587
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