Given that x̄ = 32, n = 49, and σ σ = 3, then we can be 95% confident that the true mean, μ μ , lies between the values
and
Solution :
Given that,
Sample size = n = 49
Z/2 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * (3 / 49)
= 0.84
At 95% confidence interval estimate of the population mean is,
- E < < + E
32 - 0.84 < < 32 + 0.84
31.16 < < 32.84
Between the values 31.16 and 32.84
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