given normal random variable x with mean μ= 57.1 and standard deviation σ=13.2, what is P (46 < x̄ < 69) for a sample of size n= 16?
Solution :
=
/
n = 13.2 /
16 = 3.3
= P[(46 - 57.1) / 3.3< (
-
)
/
< (69 - 57.1) / 3.3)]
= P(-3.36 < Z < 3.61)
= P(Z < 3.61) - P(Z < -3.36)
= 0.9998 - 0.0004
= 0.9994
P(46 <
< 69) = 0.9994
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