Question

Suppose the probability of an adult male being more than

6 feet tall is 20%, the probability of an adult male having both
biological parents of above

average height is 10%, and the probability of an adult male having
both biological parents

of above average height is 40% given that the adult male is more
than 6 feet tall. What is

the probability that an adult male is more than 6 feet tall given
that both of his biological

parents are of above average height? Please simplify your answer to
a decimal value and

circle your answer. Ensure you show your work

Answer #1

The inforrmations provided from the question:

P[ height of an adult male being more than 6 feet] =0.2

P[an adult male having both biological parents of above average height]=0.1

P[ an adult male having both biological parents of above average height | adult male is more than 6 feet tall]= 0.4

So, P[ adult male is more than 6 feet tall | both of his biological parents are of above average height]

= P[ an adult male having both biological parents of above average height | adult male is more than 6 feet tall]*P[adult male is more than 6 feet tall]/ P[an adult male having both biological parents of above average height]

[by Bayes' Theorem, P[A|B]=P[A and B]/P[B]=P[B|A]*P[A]/P[B] ]

= 0.4*0.2/0.1=0.8 [answer]

According to the National Health Survey, the heights of adult
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Case
Hospitalized?
Gender
Age
Insured
Count of Patients
1
Yes
Male
>65
Yes
10
2
Yes
Male
<65
Yes
20
3
Yes
Female
>65
Yes
30
4
Yes
Female
<65
No
40
5
No
Male
>65
No
20
6
No
Male
<65
No
40
7
No
Female
>65
No
60
8
No
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<65
No
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