Please provide the solution in excel. Thank you.
Consider investing in your stock and assume that the daily change is normally distributed. Using your mean and standard deviation, determine the probability for the average of 9 daily changes of this stock to have: (how do I do this? It won't let me post the entire history. Here are the first 9 days )
Part 2C: If you wanted to be 95% sure what the daily change would be, what range for a daily change would you expect?
Date | Open | High | Low | Close | Adj Close | Volume | Daily Change |
11/22/2019 | $ 52.96 | $ 53.19 | $ 52.75 | $ 53.03 | $ 53.03 | $ 9,113,300.00 | $ 0.07 |
11/21/2019 | $ 53.11 | $ 53.34 | $ 52.78 | $ 52.96 | $ 52.96 | $ 7,856,100.00 | $ (0.15) |
11/20/2019 | $ 53.10 | $ 53.40 | $ 53.01 | $ 53.22 | $ 53.22 | $ 11,970,300.00 | $ 0.12 |
11/19/2019 | $ 53.15 | $ 53.31 | $ 52.87 | $ 53.08 | $ 53.08 | $ 12,679,500.00 | $ (0.07) |
11/18/2019 | $ 52.68 | $ 53.44 | $ 52.67 | $ 53.03 | $ 53.03 | $ 13,782,000.00 | $ 0.35 |
11/15/2019 | $ 52.64 | $ 52.68 | $ 52.38 | $ 52.67 | $ 52.67 | $ 8,982,400.00 | $ 0.03 |
11/14/2019 | $ 52.53 | $ 52.67 | $ 52.35 | $ 52.63 | $ 52.63 | $ 8,660,300.00 | $ 0.10 |
11/13/2019 | $ 52.18 | $ 52.45 | $ 51.96 | $ 52.41 | $ 52.41 | $ 12,257,900.00 | $ 0.23 |
11/12/2019 | $ 51.91 | $ 51.91 | $ 51.58 | $ 51.71 | $ 51.71 | $ 12,656,900.00 | $ (0.20) |
Coca Cola Daily Change |
|
Mean | -0.09625 |
Standard Error | 0.063183 |
Median | -0.025 |
Mode | -0.22 |
Standard Deviation | 0.357417 |
Sample Variance | 0.127747 |
Kurtosis | -0.296618 |
Skewness | -0.310166 |
Range | 1.399998 |
Minimum | -0.82 |
Maximum | 0.579998 |
Sum | -3.08001 |
Count | 32 |
Confidence Level (95.0%) | 0.128863 |
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