Question

A newsgroup is interested in constructing a 90% confidence
interval for the difference in the proportions of Texans and New
Yorkers who favor a new Green initiative. Of the 605 randomly
selected Texans surveyed, 396 were in favor of the initiative and
of the 579 randomly selected New Yorkers surveyed, 457 were in
favor of the initiative.

a. With 90% confidence the difference in the proportions of Texans
and New Yorkers who favor a new Green initiative is between (round
to 3 decimal places) and (round to 3 decimal places).

b. If many groups of 605 randomly selected Texans and 579 randomly
selected New Yorkers were surveyed, then a different confidence
interval would be produced from each group. About percent of these
confidence intervals will contain the true population proportion of
the difference in the proportions of Texans and New Yorkers who
favor a new Green initiative and about percent will not contain the
true population difference in proportions.

Answer #1

The statistical software output for this problem is:

From above output:

a) 90% confidence interval:

(-**0.177, -0.092**)

b) First blank = **90**

Second blank = **10**

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