Question

A sample of 100 of a particular brand of tires found the mean life span to...

A sample of 100 of a particular brand of tires found the mean life span to be 50,000 miles . The population standard deviation is 800 miles . (a) Construct a 90% confidence interval containing the mean life span of all tires.
(b) How large must the sample be in order to be 90% confident that the mean lifespan of tires is within 500 miles of the sample mean ?
(c) How could we reduce the margin of error?
Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A manufacturer claims that the life span of its tires is 50,000 miles. You work for...
A manufacturer claims that the life span of its tires is 50,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100 tires at random and test them. The mean life span is 49 comma 785 49,785 miles. Assume sigma σ equals = 800 (ROUND TO FOUR DECIMALS)
A manufacturer claims that the life span of its tires is 52,000 miles. You work for...
A manufacturer claims that the life span of its tires is 52,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100 tires at random and test them. The mean life span is 51.831 miles. Assume sigma = 800. Complete parts​ (a) through​ (c). (a) Assuming the​ manufacturer's claim is​ correct, what is the probability that the mean of the sample is 51,831...
A manufacturer claims that the life span of its tires is 51,000 miles. You work for...
A manufacturer claims that the life span of its tires is 51,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100 tires at random and test them. The mean life span is 50,844 miles. Assume σ = 800. Complete parts​ (a) through​ (c). a.) Assuming the​ manufacturer's claim is​ correct, what is the probability that the mean of the sample is 50,844...
A manufacturer claims that the life span of its tires is 51,000 miles. You work for...
A manufacturer claims that the life span of its tires is 51,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100 tires at random and test them. The mean life span is 50,723 miles. Assume sigmaσequals=800. Complete parts​ (a) through​ (c). ​(a) Assuming the​ manufacturer's claim is​ correct, what is the probability that the mean of the sample is 50 comma 72350,723...
A particular brand of tires claims that its snow tire averages less than 50,000 miles before...
A particular brand of tires claims that its snow tire averages less than 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8,000. A survey of owners of that tire design is conducted. From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9,800 miles. Using α = 0.05 to test the claim.
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before...
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000. A survey of owners of that tire design is conducted. Of the 26 tires in the survey, the average lifespan was 46,700 miles with a standard deviation of 9800 miles. Do the data support the claim at the 5% level? Could someone explain how to...
A manufacturer claims that the life span of its tires is 48,000 miles. You work for...
A manufacturer claims that the life span of its tires is 48,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select one hundred tires at random and test them. The mean life span is 47,858 miles. Assume sigmaσequals=900 Complete parts​ (a) through​ (c). ​(a) Assuming the​ manufacturer's claim is​ correct, what is the probability that the mean of the sample is 47,858 miles...
A manufacturer claims that the life span of its tires is 52 comma 00052,000 miles. You...
A manufacturer claims that the life span of its tires is 52 comma 00052,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100100 tires at random and test them. The mean life span is 51 comma 79951,799 miles. Assume sigma?equals=700700. Complete parts? (a) through? (c). ?(a) Assuming the? manufacturer's claim is? correct, what is the probability that the mean of the sample...
A manufacturer claims that the life span of its tires is 52 comma 000 miles. You...
A manufacturer claims that the life span of its tires is 52 comma 000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100 tires at random and test them. The mean life span is 51 comma 729 miles. Assume sigmaequals900. Complete parts​ (a) through​ (c). ​(a) Assuming the​ manufacturer's claim is​ correct, what is the probability that the mean of the sample...
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before...
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8,000. A survey of owners of that tire design is conducted. Of the 29 tires surveyed, the mean lifespan was 46,600 miles with a standard deviation of 9,800 miles. Using alpha = 0.05, is the data highly consistent with the claim? Note: If you are using...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT