Question

Using the following information:

For the first population: sample size of 30 taken from the population, sample mean 1.32 , population variance 0.9734.

For the second population : sample size of 30 taken from the population, sample mean 1.04,

population variance 0.7291.

Find a 90% confidence interval for the difference between the two population means.

Answer #1

A sample of size 10 is taken from the first population: Sample
mean of 101.2 and sample variance of 18.1
A sample of size 14 is taken from the second population: Sample
mean of 98.7 and sample variance of 9.7
a)In order to decide whether pooling is appropriate or not,
performing a test at α = 0.2 level of significance : Find the
rejection region.
b)In order to decide whether pooling is appropriate or not,
performing a test at α...

A sample of size 10 is taken from the first population: Sample
mean of 101.2 and sample variance of 18.1
A sample of size 14 is taken from the second population: Sample
mean of 98.7 and sample variance of 9.7
a)In order to decide whether pooling is appropriate or not,
performing a test at α = 0.2 level of significance : Find the
rejection region.
b)In order to decide whether pooling is appropriate or not,
performing a test at α...

A sample of size 10 is taken from the first population: Sample
mean of 101.2 and sample variance of 18.1
A sample of size 14 is taken from the second population: Sample
mean of 98.7 and sample variance of 9.7
1)In order to decide whether pooling is appropriate or not,
performing a test at α = 0.2 level of significance : Find the
rejection region.
2)In order to decide whether pooling is appropriate or not,
performing a test at α...

A sample of size 30 is taken from the population of morel
mushrooms and used to calculate an average height x ¯ = 4.6
centimeters.. Suppose the sample standard deviation is calculated
to be s =0.5. What is the margin of error for a 90% confidence
interval? Round your answer to 3 decimal places.

A sample of size 6 is taken from a population with an unknown
variance. The sample mean is 603.3 and the sample standard
deviation is 189.8. Calculate a 95% confidence interval. What is
the upper limit of the interval? Enter your answer to 1 decimal
places.

A sample of size 52 is taken from a population with an unknown
variance. The sample mean is 965.3 and the sample standard
deviation is 5.5. Calculate a 99.9% confidence interval. What is
the upper limit of the interval? Enter your answer to 1 decimal
places.

consider the following results frmo two independent random
samples taken from two populations. assume that the variances are
NOT equal.
Population 1
population 2
sample size
50
50
sample mean
35
30
sample variance
784
100
a) what is the "degrees of freedom" for these data?
b) what is the 95% confidence interval difference of the
population means?

A random sample of size is taken from a population that has a
variance of 49. The sample mean is 90.4, n = 9. Construct a 80%
confidence interval for μ.
Please show steps

Consider the following results for two independent random
samples taken from two populations.
Sample 1
Sample 2
n 1 = 40
n 2 = 30
x 1 = 13.4
x 2 = 11.9
σ 1 = 2.3
σ 2 = 3.2
What is the point estimate of the difference between the two
population means? (to 1 decimal)
Provide a 90% confidence interval for the difference between
the two population means (to 2 decimals). Use
z-table.
( , )
Provide a...

A random sample of size 15 taken from a normally
distributed population revealed a sample mean of 75 and a sample
variance of 25. The upper limit of a 95% confidence interval for
the population mean would equal:
Group of answer choices
72.727.
77.273.
77.769.
72.231.

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