A random sample of size 15 taken from a normally distributed population revealed a sample mean of 75 and a sample variance of 25. The upper limit of a 95% confidence interval for the population mean would equal:
Group of answer choices
72.727.
77.273.
77.769.
72.231.
here we do not have the population variance and the data is normally distributed so we can use the t-dist for the population mean interval.
(1- )% is the confidence interval for population mean
Where 75
n = 15
Sx = ....................where var = 25
Alpha =1 - 0.95 = 0.05
Therefore the C.V. =
=
= 2.14479 .............found using t-dist tables
Substituting the value
Where Margin of error = C.v. * SE
=
The upper limit =
The tail is not mentioned so we assume it is two tailed.
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