The Richardson marketing research firm asks you, the analyst, to examine whether the sample of 100 satisfaction ratings provide evidence to support the claim that the population mean u exceeds 50.
(a) How is the sample distributed? Why?
(b) Assume the population mean u=50, x is all the possible sample means, calculate the mean u(x) for all the possible sample means.
(c) Assume the population standard deviation sigma=3.35, x is all the possible sample means, calculate the standard deviation sigma(x) for all the possible sample means.
(d) Based on 1b and 1c above, what is the probability of observing a sample mean above 50.99?
(e) If u=50, what is the percentage for all the possible sample means to be above 50.99? What is your conclusion about this percentage?
Sample means x | |||
u= | n= | sigma= | |
sigma(x)=sigma/sqrt(n) | |||
P(X>) | norm.dist | ||
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