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The Richardson marketing research firm asks you, the analyst, to examine whether the sample of 100...

The Richardson marketing research firm asks you, the analyst, to examine whether the sample of 100 satisfaction ratings provide evidence to support the claim that the population mean u exceeds 50.

(a) How is the sample distributed? Why?

(b) Assume the population mean u=50, x is all the possible sample means, calculate the mean u(x) for all the possible sample means.

(c) Assume the population standard deviation sigma=3.35, x is all the possible sample means, calculate the standard deviation sigma(x) for all the possible sample means.

(d) Based on 1b and 1c above, what is the probability of observing a sample mean above 50.99?

(e) If u=50, what is the percentage for all the possible sample means to be above 50.99? What is your conclusion about this percentage?

Sample means x
u= n= sigma=
sigma(x)=sigma/sqrt(n)
P(X>) norm.dist
Math   Statistics-And-Probability   
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