Question

It is known that 60% of the students at a large university have a job and 40% do not have a job. If two of these students are randomly selected what is the probability that one will have a job and one will not have a job?

Answer 1

It is known that 60% of the students at a large university have a job and 40% do not have a job. If two of these students are randomly selected what is the probability that one will have a job and one will not have a job

P(Atleast one out of three does not have a job)

= 1 - P(All three have a job)

= 1 - (0.60)³

= 0.784

P(One will have a job and one will not have a job)

= 0.480

Student have a job (p) = 60% = 0.60

Student have not a job (1-p) = 40% = 0.40

3 students are randomly selected.

Now, we have to find probability all 3 have job

P(all 3 have a job ) = p*p*p = 0.60 * 0.60 * 0.60 = 0.216