Question

In PYTHON,

Write a function formatLongDate that will accept a date in the form mm/dd/yy as a string argument. Your program should take the string apart (hint: use an appropriate string function) into month, day and year variables. Return the date in the long format (e.g. 09/30/05 would be output as September 30, 2005). You may assume all years yy are in the 21^st century. For instance:

>>> formatLongDate("09/05/99")

September 5, 2099

September 5, 2099

Answer 1

def formatLongDate(s):
    lst = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
    values = s.split("/")
    month = lst[int(values[0])-1]
    day = values[1]
    year = "20"+values[2]
    return month+" "+day+", "+year

# Testing
print(formatLongDate("09/05/99"))

September 05, 2099