Question

Predict a student’s GPA (y) based upon the number of hours studied per week (x). Hours/week...

Predict a student’s GPA (y) based upon the number of hours studied per week (x).

Hours/week

GPA

5

2.5

10

3.1

12

3.3

20

3.8

15

3.7

12

3.5

If you used the least-squares regression line to predict the GPA of a student who studied 40 hours per week that would be:

a) residual

b) interpolation

c) extrapolation

d) r2

Homework Answers

Answer #1

extrapolation (C)

[ explanation:-

here, we will extrapolate , because the value 40 hours, is outside the data set .here,the largest number of hours was 20, but the extrapolation tried to jump to 40 hour.

the regression equation is :-

GPA = 2.218 +0.0891 x

the predicted GPA score for a student who studied 40 hours per week would be:-

= 2.218 + (0.0891*40) = 5.782 ...which is supposed to be overestimated.

the option interpolation is not true:-

because interpolation is used when the value is within the data set.but, here the value 40 is outside the data range. ]

*** if you have any doubt regarding the problem ,please write it in the comment box...if satisfied,please UPVOTE

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Predict a student’s GPA (y) based upon the number of hours studied per week (x). Hours/week...
Predict a student’s GPA (y) based upon the number of hours studied per week (x). Hours/week GPA 5 2.5 10 3.1 12 3.3 20 3.8 15 3.7 12 3.5 Using the correct answer from the previous question, predict the GPA of someone who studies 10 hours? a) 2.5 b) 2.7 c) 2.9 d) 3.1
Predict a student’s GPA (y) based upon the number of hours studied per week (x). Hours/week...
Predict a student’s GPA (y) based upon the number of hours studied per week (x). Hours/week GPA 5 2.5 10 3.1 12 3.3 20 3.8 15 3.7 12 3.5 Find the correlation. a) .961 b) .978 c) .956 d) .939
Estimate: GPA = β0 + β1GRE + ε, where GRE is a student’s score on the...
Estimate: GPA = β0 + β1GRE + ε, where GRE is a student’s score on the math portion of the Graduate Record Examination (GRE) score and GPA is the student’s grade point average in graduate school. [You may find it useful to reference the t table.] a. Construct the 90% confidence interval for the expected GPA for an individual who scored 710 on the math portion of the GRE. (Round regression estimates to at least 4 decimal places, "tα/2,df" value...
The Data below represents number of hours students’ study Mathematics per week and their corresponds GPA...
The Data below represents number of hours students’ study Mathematics per week and their corresponds GPA –(GPA is based on 0 to 4) Hours of Study GPA 4 3 4.5 3 5 3.33 5 3 6 3.67 7 3.5 7 3.5 8 4 4.5 4 6 3 7 4 6 3.5 8 3.67 Draw the Scatter Diagram considering “x” as study time and “y” as the GPA of a student. Find the predicted linear equation, then describe the domain and...
A least squares regression line to predict a student’s Stat145 test score (from 0-to-100) from the...
A least squares regression line to predict a student’s Stat145 test score (from 0-to-100) from the number of hours studied was determined from a class of 55 Stat145 students: ̂ = 46.2 + 2.71x. One student in the class studied for 16 hours and scored 87 on the exam. (a) (5 pts.) What is the predicted value of this student’s Stat145 exam score? (b) (5 pts.) What is the residual for this student? (c) (5 pts.) Explain what the slope...
Consider the following data on the number of hours taht 7 persons studied for a French...
Consider the following data on the number of hours taht 7 persons studied for a French test and their scores on the test Hours studied (x) 3 9 14 4 3 12 10 Test score (y) 20 60 80 30 25 70 60 a) Find the equation of the least squares line that approximates the regression of the test scores on the number of hours studied b) Predict the average test score of a person who studied 14 hours for...
We study the relation between students' GPA and the number of hours per week spent studying....
We study the relation between students' GPA and the number of hours per week spent studying. To this end, we consider the following regression model, GPA = β 0 + β 1 hours+u where GPA is the variable measuring students' GPA, hours is the variable measuring the number of hours studying, and u is the error term. We found the following OLS estimates: β ^ 0 = 2.67 β ^ 1 = 0.601 What is the predicted GPA of a...
You are given the following bivariate data about hours spent studying versus test grade in percent....
You are given the following bivariate data about hours spent studying versus test grade in percent. Below is the data collected from 5 different students. Studytime(hr) | test Grade(%) 2.0 72.4 2.5 77.0 3.5 86.0 4.0 94.8 5.5 97.1 Let x be the hour spent studying and y be the test grade in percent. Using the data above, we have the following: n = 5, x ̄ = 3.5, y ̄ = 85.46, sx = 1.369306, sy = 10.78369, r...
Six small Oregon cities give the following information about x and y values: per capita income...
Six small Oregon cities give the following information about x and y values: per capita income in thousands(x) 8.6 9.3 10.1 8.0 8.3 8.7 number of medical doctors(y) 9.6 18.5 20.9 10.2 11.4 13.1 a) Make a scatterplot. Label your axes and the scales used. b) What is the linear correlation coefficient? c) Compute the equation of the least squares regression line. d) What percent of the relationship between x and y is explained by a line? e) Graph the...
For questions #47-50, refer to the following: A possible linear correlation between(x) hours of exercise per...
For questions #47-50, refer to the following: A possible linear correlation between(x) hours of exercise per week and (y) a person's cholesterol level was examined with the following results: (x): 5 12 3 1 4 7 (y): 212 165 178 195 210 145 #47) What is the correlation coefficient? a. .87 b. .63 c. -.53 d. -.43 e. -.27 What percentage of a person's cholesterol level is directly related to their hours of weekly exercise? a. .28 b. 28.09 c....