Question

How much does a sleeping bag cost? Let's say you want a sleeping bag that should keep you warm in temperatures from 20°F to 45°F. A random sample of prices ($) for sleeping bags in this temperature range is given below. Assume that the population of x values has an approximately normal distribution.

110	70	50	55	95	50	30	23	100	110
105	95	105	60	110	120	95	90	60	70

(a) Use a calculator with mean and sample standard deviation keys to find the sample mean price x-bar and sample standard deviation s. (Round your answers to two decimal places.)

x-bar =	$
s =	$

(b) Using the given data as representative of the population of prices of all summer sleeping bags, find a 90% confidence interval for the mean price μ of all summer sleeping bags. (Round your answers to two decimal places.)

lower limit	$
upper limit	$

Answer 1

a)
xabr = 80.15
s = 28.93

b)

sample mean, xbar = 80.15
sample standard deviation, s = 28.93
sample size, n = 20
degrees of freedom, df = n - 1 = 19

Given CI level is 90%, hence α = 1 - 0.9 = 0.1
α/2 = 0.1/2 = 0.05, tc = t(α/2, df) = 1.729

ME = tc * s/sqrt(n)
ME = 1.729 * 28.93/sqrt(20)
ME = 11.2

CI = (xbar - tc * s/sqrt(n) , xbar + tc * s/sqrt(n))
CI = (80.15 - 1.729 * 28.93/sqrt(20) , 80.15 + 1.729 * 28.93/sqrt(20))
CI = (68.97 , 91.33)

lower limit = 68.97	$
upper limit = 91.33