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Scores for an test are normally distributed with a mean of 275 and a standard deviation...

Scores for an test are normally distributed with a mean of 275 and a standard deviation of 60. How high must an individual score to be in the highest 10%? Please round to the nearest whole number.

Math   Statistics-And-Probability   
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Answer #1

Given that the scores for a test are normally distributed with a mean of = 275 and a standard deviation of = 60.

Thus for a normally distributed to find the minimum score to get in the top 10% of the distribution the Z score is calculated using the excel formula for normal distribution which is =NORM.S.INV(1-0.10), thus the Z score is computed as 1.282.

Now based on the Z score formula the minimum score to be in highest 10% is calculated as:

Thus the individual score should be at least 350 to be in the top 10%,

Note: Feel free to ask if query remains

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