Question

Given that X is a geometric random variable with success probability = 1/3, Find Pr(X<1003 |...

Given that X is a geometric random variable with success probability = 1/3, Find Pr(X<1003 | X>1000). (Hint: must use memory-less property of geometric random variables).

Homework Answers

Answer #1

The solution is done showing all steps with calculations and required formulas. Hope you can understand.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Let Y denote a geometric random variable with probability of success p, (a) Show that for...
Let Y denote a geometric random variable with probability of success p, (a) Show that for a positive integer a, P(Y > a) = (1 − p) a (b) Show that for positive integers a and b, P(Y > a + b|Y > a) = P(Y > b) = (1 − p) b This is known as the memoryless property of the geometric distribution.
(14pts) Let X and Y be i.i.d. geometric random variables with parameter (probability of success) p,...
(14pts) Let X and Y be i.i.d. geometric random variables with parameter (probability of success) p, 0 < p < 1. (a) (6pts) Find P(X > Y ). (b) (8pts) Find P(X + Y = n) and P(X = k∣X + Y = n), for n = 2, 3, ..., and k = 1, 2, ..., n − 1.
If the random variable X follows a binomial distribution with the probability of success given by...
If the random variable X follows a binomial distribution with the probability of success given by p, show that the variance of X is equal to np(1-p). [Hint:Consider first a Bernoulli probability distribution with n=1.]
How to use Chebyshev bound to achieve this question ? Let X be a Geometric random...
How to use Chebyshev bound to achieve this question ? Let X be a Geometric random variable, with success probability p. 1) Use the Markov bound to find an upper bound for P (X ≥ a), for a positive integer a. 2) If p = 0.1, use the Chebyshev bound to find an upper bound for P(X ≤ 1). Compare it with the actual value of P (X ≤ 1) which you can calculate using the PMF of Geometric random...
Assume the random variable X has a binomial distribution with the given probability of obtaining success....
Assume the random variable X has a binomial distribution with the given probability of obtaining success. Find the following probability, given the number of trials and the probability of obtaining success. Round your answer to four decimal places. P(X≥7), n=10, p=0.3
Assume the geometric distribution applies. Use the given probability of success p to find the indicated...
Assume the geometric distribution applies. Use the given probability of success p to find the indicated probability. Find ​P(6) when p=0.80
Suppose X and Y are independent Geometric random variables, with E(X)=4 and E(Y)=3/2. a. Find the...
Suppose X and Y are independent Geometric random variables, with E(X)=4 and E(Y)=3/2. a. Find the probability that X and Y are equal, i.e., find P(X=Y). b. Find the probability that X is strictly larger than Y, i.e., find P(X>Y). [Hint: Unlike Problem 1b, we do not have symmetry between X and Y here, so you must calculate.]
Let X1 and X2 be two independent geometric random variables with the probability of success 0...
Let X1 and X2 be two independent geometric random variables with the probability of success 0 < p < 1. Find the joint probability mass function of (Y1, Y2) with its support, where Y1 = X1 + X2 and Y2 = X2.
Let X be a geometric random variable with parameter p . Find the probability that X≥10...
Let X be a geometric random variable with parameter p . Find the probability that X≥10 . Express your answer in terms of p using standard notation (click on the “STANDARD NOTATION" button below.)
Assume the random variable X has a binomial distribution with the given probability of obtaining a...
Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. Round your answer to four decimal places. P(X>3)P(X>3), n=5, p=0.8