Question

The life time of a lamp X follows exp(λ = 1/3 per hour). Hence, on average,...

  1. The life time of a lamp X follows exp(λ = 1/3 per hour). Hence, on average, 1 failure per 3 hours.

  1. Find the probability that the lamp lasts longer than its mean life.
  1. The probability that the lamp lasts between 2 to 3 hours.
  1. Find the probability that it lasts for another hour given it is operating for 2.5 hours. (6pts)

Homework Answers

Answer #1

TOPIC:Exponential distribution.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The life time of a lamp X follows exp(λ = 1/3 per hour). Hence, on average,...
The life time of a lamp X follows exp(λ = 1/3 per hour). Hence, on average, 1 failure per 3 hours. a) Find the probability that the lamp lasts longer than its mean life. b) The probability that the lamp lasts between 2 to 3 hours. c) Find the probability that it lasts for another hour given it is operating for 2.5 hours.
X is a team useful life, X~Exp(λ=0.02) find: μ, σ P(X>3) P(1<X<4) P(X>a)=0.01, what is the...
X is a team useful life, X~Exp(λ=0.02) find: μ, σ P(X>3) P(1<X<4) P(X>a)=0.01, what is the value of a? P(X>3/X>1)
Poisson Distribution: p(x, λ)  =   λx  exp(-λ) /x!  ,  x = 0, 1, 2, ….. Find the moment generating function Mx(t)...
Poisson Distribution: p(x, λ)  =   λx  exp(-λ) /x!  ,  x = 0, 1, 2, ….. Find the moment generating function Mx(t) Find E(X) using the moment generating function 2. If X1 , X2 , X3  are independent and have means 4, 9, and 3, and variencesn3, 7, and 5. Given that Y = 2X1  -  3X2  + 4X3. find the mean of Y variance of  Y. 3. A safety engineer claims that 2 in 12 automobile accidents are due to driver fatigue. Using the formula for Binomial Distribution find the...
1) If the lamp of 119.05 W is on for an average of 6 hours per...
1) If the lamp of 119.05 W is on for an average of 6 hours per day, and if peak sun hours average 6 hours per day, • Determine the power output required for a PV array that would power the lamp, assuming 10% degradation of the PV array. • Determine a general expression for PV array power as a function of lamp operating time, assuming full utilization of the PV output.
The length of time in hours that a certain part lasts follows a Weibull distribution with...
The length of time in hours that a certain part lasts follows a Weibull distribution with parameters α = 2 and β = 2. a. What are the mean and standard deviation of this distribution? b. What is the probability that the part lasts less than 1 hour? c. What is the equation for the failure rate of the part? d. If the distribution is actually Gamma instead of Weibull find the equation for the failure rate of the part...
X is a team lifetime, X~Exp(λ=0.02) find: μ, σ P(X>3) P(1<X<4) P(X>a)=0.01, what is the value...
X is a team lifetime, X~Exp(λ=0.02) find: μ, σ P(X>3) P(1<X<4) P(X>a)=0.01, what is the value of a? P(X>3/X>1)
let X be a random variable that denotes the life (or time to failure) in hours...
let X be a random variable that denotes the life (or time to failure) in hours of a certain electronic device. Its probability density function is given by f(x){ 0.1 e−0.1x, x > 0 , 0 , elsewhere (a) What is the mean lifetime of this type of device? (b) Find the variance of the lifetime of this device. (c) Find the expected value of X2 − 20X + 100.
1. A restaurant serves an average of 180 customers per hour during the lunch time. (a)....
1. A restaurant serves an average of 180 customers per hour during the lunch time. (a). What probability distribution is most appropriate for calculating the probability of a given number of customers arriving within one hour during lunch time? (b). What are the mean and the standard deviation of the number of customers this restaurant serves in one hour during lunch time? (c). Would it be considered unusually low if only 150 customers showed up to this restaurant in one...
Arrival Rate = 1/50 = 0.02 calls hour. Service Rate= 1 hour (travel time) + 1.5...
Arrival Rate = 1/50 = 0.02 calls hour. Service Rate= 1 hour (travel time) + 1.5 hour (repair time) =2.5 hours With m = 1/ 2.5 = 0.4 hours per customers ** PLEASE SHOW HOW TO DO EQUATION ** OEI is satisfied that one service technician can handle the 10 existing customers. Use a waiting line model to determine the following information: (a) probability that no customers are in the system, (b) average number of customers in the waiting line,...
1) A queuing model that follows the M/M/1 (single channel) assumptions has λ = 10 per...
1) A queuing model that follows the M/M/1 (single channel) assumptions has λ = 10 per hour and μ = 2.5 minutes. What is the average time in the system (in minutes)? Group of answer choices: .41 minutes .5 minutes 25 minutes 1.78 minutes 4.29 minutes 2) A waiting-line system that meets the assumptions of M/M/S (multi-channel) has λ = 4 every 12 minutes, μ = 4 minutes, and M = 2. For these values, Po is approximately 0.2, and...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT