Let random variable x be a continous random variable and it’s
probabilty density function is given as;
f(x) = 3x^2 , 0 < x < 1
So find the probabilty that the random variable x exceeds the value
of 1/2
(single random variable question)
Let X be a random variable with th peobability density function given by
The probability that random variable X exceeds the value of 1/2 is obtained by considering the probability of X>1/2. X can take any value greater than 1/2 but we consider only upto the highest value it can take which is 1 as the value of density f(x), outside it is 0. It indicates that the area of the region for X>1/2 under X lies in (0, 1) which is given by P(X>1/2) and can be obtained as follows
Therefore the probability that X exceeds the value of 1/2 is 0.875
Get Answers For Free
Most questions answered within 1 hours.