Question

Exercise-2.60:

Orders for a computer are summarized by the optional features that are requested as follows

	Proportion of Orders
No optional features	0.3
One optional feature	0.5
More than one optional feature	0.2

(a) What is the probability that an order requests at least one optional feature?

(b) What is the probability that an order does not request more than one optional feature?

Answer 1

From given information we find the following probabilities,

Let X be the number of optional features.

a) We want to find, the probability that an order requests at least one optional feature. That is to find, P(X >=1)

P(X >=1) = P(X = 1) + P(X > 1) = 0.5 +0.2 = 0.7

P(X >=1) = 0.7

b) we want to find, the probability that an order does not request more than one optional feature. That is to find, P(X <= 1)

P(X <= 1) = P(X =0 ) +P(X =1) = 0.3 + 0.5 = 0.8

P(X <= 1) = 0.8