The marks of students taking a statistics examination is normally distributed with a standard deviation of 10 marks. 10% of students scored above 85 marks for the examination. Determine the percentage of students who scored above 65 marks for the examination.
Let X be the random variable indicating the score of the student in the exam.
The standard deviation = 10.
We know that
P(X > 85 ) = 0.1
This implies
P(X <= 85) = 1 - 0.1 = 0.9
Now, consider the standard normal variable z which is
Using this, we get
From the table for the standard normal variable, we get
z1 = 1.28
Comparing this value with the previous equation, we know that
We need to calculate
P(X > 65) = 0.76424
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