A random sample of 100 measurements is selected from a population with unknown mean and standard deviation of 10.
Calculate width of the 95% CI for the mean.
a. |
1.00 |
|
b. |
0.196 |
|
c. |
1.96 |
|
d. |
3.92 |
Solution :
Given that,
Population standard deviation = = 100
Sample size = n = 100
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * (10 / 100)
E = 1.96
= 1.96 * 2 = 3.92
option d) is correct
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