Question

Suppose a random sample of 25 measurements is selected from a population with a mean of 19 and a standard deviation of 1.9. What is the mean and standard error of X?

a) μ_X = 19; σ_X = 1.90

b) μ_X = 19; σ_X = 0.08

c) μ_X = 19; σ_X = 0.38

d) μ_X = 3.80; σ_X = 1.90

e) μ_X = 3.80; σ_X = 0.38

Answer 1

Solution :

Given that,

mean = = 19

standard deviation = = 1.9

n = 25

The sampling distribution of mean and standard error is ,

= 19 and

= / n = 1.9 / 25 = 0.38

= 19 :   = 0.38

option c) is correct