A sample of size n = 36 produced the sample mean of 9. Assuming the population standard deviation = 4, compute a 95% confidence interval for the population mean.
a) 8.33 ≤ μ ≤ 9.67
b) 7.04 ≤ μ ≤ 10.96
c) 5 ≤ μ ≤ 14
d) 7.69 ≤ μ ≤ 10.31
95% confidence interval for is
- Z * / sqrt(n) <= <= + Z * / sqrt(n)
9 - 1.96 * 4 / sqrt(36) <= <= 9 + 1.96 * 4 / sqrt(36)
7.69 <= <= 10.31
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