Question

If the sample mean is 75 and the sample size (n) is 36, given that the population standard deviation (σ) equals 12, construct a 99% confidence interval for the population mean (µ). What is the standard error of the mean (compute)? What are the critical values? From what distribution? What is the confidence interval (compute)? If an expert asserted that the population mean was 79, at a 99% level of confidence, would the data gathered in this sample tend to support the expert's opinion?

Answer #1

please like me my solution sir/madam

We have a sample of size n = 36 with mean x with bar on top
space equals 12. If population standard deviation, sigma equals 2,
what is the upper limit of 95% confidence interval (zα/2=1.96) of
population mean µ?

A sample mean, sample size, population standard deviation,
and confidence level are provided. Use this information to complete
parts (a) through (c) below.
x=54, n=14, σ=5, confidence level=99%
A. Use the one-mean z-interval procedure to find a confidence
interval for the mean of the population from which the sample was
drawn.
The confidence interval is from ___to___
B. Obtain the margin of error by taking half the length of the
confidence interval.
What is the length of the confidence interval?...

Given a sample size of n = 529. Let the variance of the
population be σ2 = 10.89. Let the mean of the sample be xbar = 15.
Construct a 95% confidence interval for µ, the mean of the
population, using this data and the central limit theorem.
Use Summary 5b, Table 1, Column 1
What is the standard deviation (σ) of the population?
What is the standard deviation of the mean xbar when the sample
size is n, i.e....

A sample of size n = 36 produced the sample mean of 9. Assuming
the population standard deviation = 4, compute a 95% confidence
interval for the population mean.
a) 8.33 ≤ μ ≤ 9.67
b) 7.04 ≤ μ ≤ 10.96
c) 5 ≤ μ ≤ 14
d) 7.69 ≤ μ ≤ 10.31

A simple random sample of size n equals 40 is drawn from a
population. The sample mean is found to be x overbar equals 120.2
and the sample standard deviation is found to be s equals 13.2.
Construct a 99% confidence interval for the population mean.

A simple random sample size of 40 is drawn from a population.
The sample mean is found to be x overbar equals 120.1x=120.1
and the sample standard deviation is found to be
s equals 12.8s=12.8.
Construct a 99% confidence interval for the population
mean.

A simple random sample of size
n equals n=40
is drawn from a population. The sample mean is found to be
x overbar equals x=121.2
and the sample standard deviation is found to be
s equals s=12.4.
Construct a 99% confidence interval for the population
mean.
Find the lower and upper bounds.

A simple random sample of size n equals n=40 is drawn from a
population. The sample mean is found to be x=120.4 and the sample
standard deviation is found to be s equals s=12.5. Construct a 99%
confidence interval for the population mean.
a) The lower bound is __
b) The upper bound is ___
(Round to two decimal places as needed.)

A simple random sample of size n equals 40n=40 is drawn from a
population. The sample mean is found to be x overbar equals
121.6x=121.6 and the sample standard deviation is found to be s
equals 12.4s=12.4. Construct a 99% confidence interval for the
population mean. The lower bound is _____. The Upper bound is
____.

A random sample of size 36 has sample mean 12 and sample
standard deviation 3. (a) Check Requirements: Is it appropriate to
use a Student’s t distribution to compute a conﬁdence interval for
the population mean ? Explain. (b) Find a 80% conﬁdence interval
for µ. [round E to 2 d.p.] (c) Interpretation: Explain the meaning
of the conﬁdence interval you computed.

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