Question

The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 12001200 voters in the town and found that 63%63% of the residents favored construction. Using the data, a political strategist wants to test the claim that the percentage of residents who favor construction is not equal to 66%66%. Testing at the 0.050.05 level, is there enough evidence to support the strategist's claim?

a) State the null and alternative hypothesis.

b) test statistic

c) One tailed or two tailed?

d) What is the P-value of the test statistic?

e)Identify the level of significance for the hypothesis test.

f) Reject or fail to reject the null hypothesis?

Answer 1

Solution :

This is the two tailed test . (two tailed)

The null and alternative hypothesis is

H₀ : p = 0.66

H_a : p 0.6

= 0.63

Test statistic = z

= - P₀ / [P_{0 *} (1 - P₀ ) / n]

= 0.63 - 0.66 / [(0.66 * 0.34) / 1200]

= -2.194

P-value = 0.0282

= 0.05

P-value <

Reject the null hypothesis .