Ben climbs the 50 steps to his apartment. At each minute, he rolls a fair die and ascends that number of steps. Assume the rolls are independent. Use Chebechev’s inequality to find a bound on the probability that he will reach his house within 12 minutes.
hre for a die P(x)=1/6 where x=1,2,3,4,5,6
x | f(x) | xP(x) | x2P(x) |
1 | 1/6 | 0.167 | 0.167 |
2 | 1/6 | 0.333 | 0.667 |
3 | 1/6 | 0.500 | 1.500 |
4 | 1/6 | 0.667 | 2.667 |
5 | 1/6 | 0.833 | 4.167 |
6 | 1/6 | 1.000 | 6.000 |
total | 3.500 | 15.167 | |
E(x) =μ= | ΣxP(x) = | 3.5000 | |
E(x2) = | Σx2P(x) = | 15.1667 | |
Var(x)=σ2 = | E(x2)-(E(x))2= | 2.9167 | |
std deviation= | σ= √σ2 = | 1.7078 |
therefore 12 minutes expected steps μ=12*3.5=42
and variance σ2 =2.9167*12=35
for Chebychev: P(X-μ>k)>=σ2/(2k2)
hence P(X-42>8) <=35/(2*82)
P(X>50)<=0.2734
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