Question

If you roll two fair dice, what is the probability that the total number of dots (or "pips") showing on the two dice is less than 6?

A. 0.417

B. 0.278

C. 0.50

D. 0.167

Answer 1

Solution:

S = {(1,1) , (1,2),.....................,(1,6)

(2,1) , ..............................,(2,6),

(3,1) , ...............................,(3,6),

(4,1),................................,(4 , 6),

(5 , 1) , ............................,(5 , 6),

(6,1),................................, (6 , 6) }

Sample space S contains 36 elements

Now ,

Event A :  total number of dots (or "pips") showing on the two dice is less than 6

A = {(1,1) , (1,2) , (1 , 3) , (1,4) , (2,1),(2,2) , (2,3),(3,1),(3,2),(4,1) }

A contains 10 elements.

So ,

P(A) = 10/36 = 0.278

Answer : 0.278