Find the conditional probability, in a single roll of two fair 6-sided dice, that the sum is less than 6, given that the sum is odd.
Sum (x) | P(x) |
2 | 1/36 |
3 | 2/36 |
4 | 3/36 |
5 | 4/36 |
6 | 5/36 |
7 | 6/36 |
8 | 5/36 |
9 | 4/36 |
10 | 3/36 |
11 | 2/36 |
12 | 1/36 |
P[ sum is less than 6, given that the sum is odd ] = P[ sum is less than 6 and the sum is odd ] / P[ the sum is odd ]
P[ sum is less than 6 and the sum is odd ] = Number of times sum is less than 6 and the sum is odd / total number of cases
P[ sum is less than 6 and the sum is odd ] = 2/36
P[ the sum is odd ] = Number of times the sum is odd / total number of cases
P[ the sum is odd ] = 5/36
P[ sum is less than 6, given that the sum is odd ] = (2/36)/(5/36)
P[ sum is less than 6, given that the sum is odd ] = 2/5
P[ sum is less than 6, given that the sum is odd ] = 0.4
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