WHERE is the for a 95 % confidence interval where the population variance is known to be 100 the sample average is 50 and the number of people samples are 64 what is the value of z what is the standard deviation what is n what is one what is the confidence interval
95% Confidence Interval for Known Population Standard Deviation
Given: = sample mean = 50, (Variance)= 100
Therefore = population standard deviation = sqrt(Variance) = sqrt(100) = 10,
n = sample size = 64
= 100 - 95 = 5% = 0.05 and Zcritical (2 tailed) = 1.96 (We can use standard normal tables or use the Excel formula NORMSINV)
The Confidence Interval is given by ME, where
The Lower Limit = 50 - 2.45 = 47.55
The Upper Limit = 50 + 2.45 = 52.45
The 95% Confidence Interval is (47.55 , 52.45)
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