The 95% confidence interval estimate for a population variance when a sample standard deviation of 12 is obtained from a sample of 61 items is
so, from the sample and for this problem we have, n = 61, s= 12,
we want a 95% confidence interval so, level of significance =0.05,
From chi-square table of critical values, we have:
,
so, using these values, 100(1-)%=95% confidence interval for is given by
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