How much work is required to move a small charge along an equipotential line? Why is the strength of the electric field (E) zero along an equipotential line?
Work required to move a charge q from potential V2 to potential V1
Since along the equipotential line, the potential remains constant, the work required to move a small charge along an equipotential line is zero
The electric field is defined as
Along an equipotential line the potential remians constant. Therefore the derivative of a constant is zero. Hence the electric field along an equipotential line is zero
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