Question

This is from an lab dealing with electric feild and equipotential lines.

1.If the electric potential between two points is zero, what does that mean in terms of the electric field in terms of the test charge?

2. Is the electric field a vector a scalar field? Explain

3. Why must equipotential lines be perpendicular to electric field lines?

4. How much work is required to move a small test charge along an equipotential line?

5. Find the electric field strength 6.0 cm from a 4.5μC charge.

6. Draw a vector diagram and calculate the electric field strength half way between a 4.5μC charge and a -4.5μC charge separated by 1.0cm

Please answer completely

Answer 1

1) the elecric field is perpendicular to the line joining the two points, work done in taking a test charge from one point to other is 0.

2) its a vector quantity as it is directed away from positive and towards negative charge

3)

so if change in potential is zero

E.l =0

E should be perpendicular to l

4) zero

5) E = kq/r²

k = 9x 10⁹ units

q =4.5μC

r = 0.06 m

plugging in the values we get

E =1.125 x 10⁷ N/C

6) electric field would be twice of electric field due to each charge

E1 =kq/r²

q =4.5μC

r = 0.5cm

plugging in we get

E1 = 1.62 x10⁹ N/C

net electric field

E =2E1 = 3.24 x 10⁹ N/C