Consider a human femur of length L = 444 mm. Model the bone as a hollow cylinder, with inner radius Ra = 5.58 mm and outer radius Rb = 16.74 mm. If a 83 kg person's weight is supported by one leg, calculate the stress on the femur; express as percentage of the ultimate compressive strength (UCS). Ignore the weight of the leg.
Correct, computer gets: 0.64
Hint: To express as a percentage of the UCS multiply by 100/UCS. Do not enter any units as they will cancel out.
7. [1pt]
Assuming that the bone follows Hooke's law up to the breaking
point, calculate the amount of compression, ΔL (in mm, don't enter
unit), that this bone can withstand before breaking.
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