On a planet far far away, Yoda is attempting to measure the magnetic field of the planet. He orients a 1500 turn, 50 cm diameter coil so that it makes an angle of 60o with the planet's magnetic field. He then rotates it so that it is parallel to the magnetic field. Because the force is strong with him, he is able to complete this rotation in 0.01 s. With his voltmeter, Yoda measures an induced emf of 1.0 V. What is the magnitude of the planet's magnetic field?
The Lenz's law gives us:
........EQ1
where, is the induced emf due to the magnetic flux change,
is the number of turns of the coil
is the magnetic flux,
is the magnetic field,
is the cross-section area aligned in direction of the magnetic field,
is the diameter of the coil
and is the time taken to change the magnetic flux.
Since magnetic field of planet is contant and the angle changes from , EQ1 modifies to (ignoring the negatice sign, as we are concerned only with the magnitude of the magnetic field):
.............EQ2
substituting values in EQ2, we get
Get Answers For Free
Most questions answered within 1 hours.