Question

2.Y While on vacation on a deserted island some irresponsible youths decide to climb a 300 m tall cliff and throw a rock horizontally off the cliff with a speed of 60 m/s (if this even possible?). A) Compute how long the rock is in the air B) How far does the rock travel horizontally before hitting the ground? C) What is the final x velocity of the rock just before it hits the ground? D) What is the final Y velocity of the rock just before it hits the ground? E) Use Matlab to plot the y position and velocity as a function of time and the x position and velocity as a function of time. Turn in plots and a copy of your code

I need the equations or definition used for so!lution with each steps!!

Answer 1

A] Initial vertical velocity = u_y = 0 m/s

use H = u_yt + (1/2)gt²

300 = 0 + (1/2)gt²

t = 7.8246 s

this is how long the rock is in the air.

B] L = u_xt = 60 x 7.8246 = 469.476 m

C] Final x velocity is 60 m/s which is the same as the initial x velocity since no acceleration is along the horizontal direction.

D] final y velocity at the bottom is: v = 0 + gt = 76.681 m/s.

E] run the script:

t = [0 : 0.2 : 7.8]

%this makes a t array

x = 60*.t

%this creates an x array

y = 0.5*9.8*(t.*t)

%this creates a y array for y=ut+(1/2)at².

plot (x,t,'--')

plot (y,t,'--')