Two cars are initially (2.50+C) km apart on a straight road. If the cars are moving toward each other, car 1 with a speed of (7.50+A) m/s and car 2 with a speed of (5.40+B) m/s, how many seconds will it take before the cars meet? Round your answer to three significant figures.
A = 7 B = 2 C = 13
A = 7
B = 2
C = 13
Initial distance between the two cars = D = (2.5 + C) = (2.5 + 13) km = 15.5 km = 15500 m
Speed of car 1 = V1 = (7.5 + A) m/s = (7.5 + 7) m/s = 14.5 m/s
Speed of car 2 = V2 = (5.4 + B) m/s = (5.4 + 2) m/s = 7.4 m/s
Time taken for the cars to meet = T
Distance traveled by car 1 = D1
D1 = V1T
Distance traveled by car 2 = D2
D2 = V2T
Total distance traveled by both the cars is equal to the initial distance between the cars.
D = D1 + D2
D = V1T + V2T
D = (V1 + V2)T
15500 = (14.5 + 7.4)T
T = 707.76 sec
Rounding off to three significant figures,
T = 708 sec
Time taken for the cars to meet = 708 sec
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