Question

A 7.65- g bullet from a 9-mm pistol has a velocity of 392.0 m/s. It strikes the 0.705- kg block of a ballistic pendulum and passes completely through the block. If the block rises through a distance h = 14.75 cm, what was the velocity of the bullet as it emerged from the block?

Answer #1

A 9.05- g bullet from a 9-mm pistol has a velocity of 353.0 m/s.
It strikes the 0.625- kg block of a ballistic pendulum and passes
completely through the block. If the block rises through a distance
h = 23.49 cm, what was the velocity of the bullet as it emerged
from the block?

A 8.65- g bullet from a 9-mm pistol has a velocity of 333.0 m/s.
It strikes the 0.665- kg block of a ballistic pendulum and passes
completely through the block. If the block rises through a distance
h = 9.79 cm, what was the velocity of the bullet as it emerged from
the block?

A 8.55- g bullet from a 9-mm pistol has a velocity of 337.0 m/s.
It strikes the 0.785- kg block of a ballistic pendulum and passes
completely through the block. If the block rises through a distance
h = 9.92 cm, what was the velocity of the bullet as it emerged from
the block?

A bullet of mass 10 g strikes a ballistic pendulum of mass 1.9
kg. The center of mass of the pendulum rises a vertical distance of
10 cm. Assuming that the bullet remains embedded in the pendulum,
calculate the bullet's initial speed.
=m/s

A bullet of mass 4.8 g strikes a ballistic pendulum of mass 3.0
kg. The center of mass of the pendulum rises a vertical distance of
18 cm. Assuming that the bullet remains embedded in the pendulum,
calculate the bullet's initial speed.

A pistol fires a 0.0050-kg bullet with a muzzle velocity of
1000.0 m/s. The bullet then strikes a 10.0-kg wooden block resting
on a horizontal frictionless surface and becomes embedded in the
block. The block and bullet then slide across the surface. What was
work done on the block and the impulse delivered to the bullet
during the collision?
a. 250J, 12.5N-s
b. 12J, 12.5N-s
c. 1.2J and -5.0N-s
d. 0.15J, -2.5N-s
e. 38J, 7.5N-s
please show work will rate!!

A 2.50 g bullet, traveling at a speed of 460 m/s, strikes the
wooden block of a ballistic pendulum, such as that in the figure
below. The block has a mass of 270 g.
(a) Find the speed of the bullet/block combination immediately
after the collision.
(b) How high does the combination rise above its initial
position?

A 75 g bullet is shot at a initial horizontal velocity
of 150 m/s and makes a completely inelastic collision with a 4.0 kg
block of wood connected to a hanging pendulum. What is the maximum
height the pendulum, containing the combined mass of the bullet and
block of wood, reaches?

In the figure here, a 11.5 g bullet moving directly upward at
1210 m/s strikes and passes through the center of mass of a 7.5 kg
block initially at rest. The bullet emerges from the block moving
directly upward at 720 m/s. To what maximum height does the block
then rise above its initial position?

A
12-g bullet moving horizontally with speed of 350 m/s strikes and
remains in a 4.0-kg block initially at rest on the edge of a table.
The block, which is initially 80 cm above the floor, strikes the
floor a horizontal distance from the base of table. What is the
horizontal distance on the floor?

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