If an electron is released at the equator and falls toward the earth under the influence of gravity, the magnetic force on the electron will be in what direction?
east = +i, North = +j and out of the page = +k
Magnetic force on a moving charge in magnetic field is given by:
F = q*VxB
q = charge on electron = -e
V = Speed of electron = V (-k) (Since given that electron is falling under the influence of gravity, So velocity will be directed into the page)
B = magnetic field of earth = B (+j) (directed north)
So,
F = -e*(-V k)x(B j)
F = e*V*B*(kxj)
In cross product: kxj = -i
F = e*V*B (-i)
-i means towards west
So force on electron will be directed towards west.
Let me know if you've any query.
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