Question

The power dissipated in a resistor is given by P=V2/R , which means power decreases if...

The power dissipated in a resistor is given by P=V2/R , which means power decreases if resistance increases. Yet this power is also given by P=I2R , which means power increases if resistance increases. Explain why there is no contradiction here.

Homework Answers

Answer #1

NEITHER eqn implies anything until you specifi the datafor a given situation. The 1st eqn makes a claim about how the power dissipated by a resistor depends on both its resistance R and te potential difference V across it. The second eqn states that te powee depends on three independednt quantities: V, I and R. However these are also related by Ohm’s law V=IR. So te two given eqns are not independent- they are connected by a third.

In P=V2R, power decreses with increasing R only if V= constant. But Ohms law then predicts that for constant V as the resistance goes up the current muat go down since I=V/R. The power in p=I2R implies that two powers of I decrese while one power of R increases, the net effect being a decrese in power- in agreement with the prediction of P=V2/R after all.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
When a flashlight is operated, what is being used up: battery current, battery voltage, battery energy,...
When a flashlight is operated, what is being used up: battery current, battery voltage, battery energy, battery power, or battery resistance? Explain your reasoning. On the other hand, the equation of power P = V2/R indicates that the power dissipated in a resistor of the flashlight decreases if the resistance is increased, whereas the equation P = I2R implies the opposite. Is there a contradiction here? Explain.
An application of the differential: estimation of small changes The power P consumed in a resistor...
An application of the differential: estimation of small changes The power P consumed in a resistor is given by P= (V^2)/R watts. Determine the approximate change in power when V increases by 5% and R decreases by 0.5% if the original values of V and R are 50 volts and 12.5 ohms respectively.
Power can be determine by using three possible ways and there are P = I x...
Power can be determine by using three possible ways and there are P = I x V, P = V2 / R and P = I2 X R. This experiment will use 2 k resistor which having resistance accuracy limitation of ±0.25%. The measurement was taken by using voltmeter with the accuracy limitation within ±0.55% of the maximum range, 10 V to measure the voltage across the resistor and an ammeter having accuracy limitation within ±0.40% of maximum range, l0mA...
1)Electrical resistance for a wire of any size can be calculated using the relation: R =...
1)Electrical resistance for a wire of any size can be calculated using the relation: R = pL/A where R = resistance ?, p = resistivity (?-cm), L = wire length (cm), p = 112 u? cm. For a 10-m length of 16-gauge (diameter = 1.291 mm) nichrome wire, find the resistance. If a current of 4 A flows in the wire, find the voltage drop and power dissipation. 2)A standard power value for a household incandescent lightbulb is 60 W....
Phsics Problem,Please show steps. A) You are given a battery, which has, of course, a particular...
Phsics Problem,Please show steps. A) You are given a battery, which has, of course, a particular emf and a particular internal resistance (Rint). You decide to determine its internal resistance and its emf by connecting an ammeter in series with a variable resistor across the battery. By varying the resistance you can draw more or less current from the battery. You also use a voltmeter to measure the voltage across the terminals of the battery. Case 1) When you draw...
On the R-S graph, given a point E, if r decreases and q decreases, the new...
On the R-S graph, given a point E, if r decreases and q decreases, the new point will be _______ point E. to the right below to the right above to the right parallel to all of the above are possible none of the above On the R-S graph, given a point E, if r decreases and q INCREASES, the new point will be _______ point E. to the right above to the right below to the right parallel to...
A Joule expansion refers to the expansion of a gas from volume V1 to volume V2...
A Joule expansion refers to the expansion of a gas from volume V1 to volume V2 against no applied pressure, and is sometimes also called a free expansion. There is no work done, because the P of -PdV is zero. By insulating the system, this process can be done adiabatically, so there is no change in heat. For an ideal gas, the adiabatic process is also isothermal, so there is no change in thermodynamic energy, ∆U = 0 (which is...
When gas expands in a cylinder with radius r, the pressure P at any given time...
When gas expands in a cylinder with radius r, the pressure P at any given time is a function of the volume V: P = P(V). The force exerted by the gas on the piston (see the figure) is the product of the pressure and the area: F = πr2P. The work done by the gas when the volume expands from volume V1 to volume V2 is W = V2 P dV V1 . In a steam engine the pressure...
Performing a physics lab where a circuit is set up with a power source that has...
Performing a physics lab where a circuit is set up with a power source that has a voltage panel. The circuit has one resistor, the value is not necessary to understand this question. The voltage across the resistor is then measured by wired voltmeter and by virtual voltmeter. When the circuit is set to be 10 V based on measurement of the wired voltmeter, the panel meter displays 7 V, the wired voltmeter displays 10 V, and the virtual voltmeter...
Question 10 of 20 Which of the following explains why international travelers need to use special...
Question 10 of 20 Which of the following explains why international travelers need to use special adapters when plugging a device designed to operate in the U.S. into a wall outlet in Europe (i.e., Vrms in the U.S. is 120 V, while Vrms in Europe is 240 V)?             The increased voltage causes the device's resistance to increase, and the device won't work.             The increased voltage causes the device's resistance to decrease, and the device will overheat.             The...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT