In a certain solar house, energy from the Sun is stored in barrels filled with water. In a particular winter stretch of five cloudy days, 0.90 ? 106 kcal per day is needed to maintain the inside of the house at 25.0
Since we know
Heat Lost by water = Heat gained by Room
Thus qin = m * C * T
Where m is mass of water needed,
C is the specific heat of water, ( 1 kcal/g )
T is the change in temperature of water; Final - inital => 50 - 25
and thus qin = 90 * 10^6 kcal/day * 5 days = 4.5 * 10^6 kcal
and qin = m * 1kcal/kg * (50-25)
=> m = 180000 kg => v = m/density = 180000/1000 = 180 m3 or 180000 Litres (Answer)
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