Question

A gas sample enclosed in a rigid metal container at room temperature (20.0∘C) has an absolute pressure p1. The container is immersed in hot water until it warms to 40.0∘C. What is the new absolute pressure p2? Express your answer in terms of p1.

p₂=_________________

Answer 1

Using Ideal gas law:

pV = nRT

Suppose initial pressure is p1

Initial Volume = V & n = number of moles & R = Gas constant

Since n, V and R remains constant, So

p/T = n*R/V = Constant

p1/T1 = p2/T2

p2 = p1*(T2/T1)

T1 = initial temperature = 20 C = 273 + 20 = 293 K

T2 = final temperature = 40 C = 273 + 40 = 313 K

So,

p2 = p1*(313/293)

p2 = 1.07*p1

Given that we need final answer in terms of p1, So include the term p1 in the final answer too.

p2 = 1.07*p1

(Again use small 'p' and not 'P')