Question

Block A of mass (mA) = 9.0 kg with an initial speed (uA) = 2.1 m/s...

Block A of mass (mA) = 9.0 kg with an initial speed (uA) = 2.1 m/s collides with a Block B of mass (mB) = 27 kg which had an in initial speed (uB) = 0.50 m/s, as shown int the figure. The surface is frictionless, and the blocks suddenly collide and couple. After the collision, Find the common speed (Vf) that the blocks travel with.

a) 0.5 m/s

b) 0.9 m/s

c) 0.1 m/s

d) 0.6 m/s

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Answer #1

Given the mass of block A (mA) = 9kg, mass of block B (mB) = 27kg, initial velocity of block A (uA) = 2.1m/s and the initial speed of block B (uB) = 0.50m/s. They collide and couple and move with a common speed Vf.

According to law of conservation of linear momentum, the total momentum before collision (Pi)is equal to the total momentum after collision (Pf). Therefore,

So the final common speed of the two blocks is 0.9m/s.

Option (b) is the correct answer.

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